Average Tips And Tricks

Average Tips And Tricks

Average: = ( Sum of observations / Number of observations ).

 

Average Methods Example 1

Example 1 :
In a School 8 student average weight is increased by 3.5 kg when new student comes in place of one of them than weight become 55 kg what might be the weight of the new student?
 

Answer :
 

Step 1: At first we find the total weight increased So, ( 8 X 3.5 )kg = 28kg.
 

Step 2: Now the weight of new Student is = ( 55 + 28 )kg = 83 kg.
So, the weight of the new student is 83 kg.

 

Example 2:
The Average weight 3 girls A, B, and C is 55kg,While the average weight of three boys B, D, and E is 57 kg. What is the average weight of A, B, C, D, E ?
 

Answer :
 

Step 1: At First we find 3 girls total weight ( A + B + C ) = ( 55 X 3 ) = 165 kg. and Total 3 boys weight of ( B + D + E ) = ( 57 x 3 ) = 171.
 

Step 2: Adding both weight of ( A + 2B + C + D + E ) = ( 165 + 171 ) = 336 kg.
Note: So, to find the average weight of A B C D and E, we duty to know B’s weight, which is not given. So the data is inadequate.

 

Average Methods Example 2

Example 1:
The average age of 34 students in a school is 15 years, after that when geography teacher’s age is added to student age then the average age increases by one, Find what is the teacher’s age in years?
 

Answer :
 

Step 1:T first we find the total student ages with out adding teacher’s age that is ( 34 x 15 ) = 510 years.
Now we find out the age of students adding with teachers age that is ( 35 x 16 ) = 560 years.
 

Step 2: Teachers age is ( 560 – 510 ) = 50 years.
 

Example 2:
The average age of 45 students in a batch is 18 years. The average age of 23 students is 16 years. Find average age of remaining 16 students ?
 

Answer :
 

Step 1: At first we find the age total age of 45 and 23students is (45 x 18 ) = 810 and ( 23 x 16 ) =368.
 

Step 2: Sum of the ages of 16 students is = ( 810 – 368 ) =  442.
So average age of is ( 442 / 16 ) = 28 years.

 

Average Methods Example 3

Example 1:
The average marks acquired by 140 students in a final examination is 36.If the average marks of failed students is 18 and the passed average students is 30. What is the passed students in examination.
 

Answer :
 

Number of passed students are = Total students(total average – failed average) / passed average – failed average
 

Step 1: = 140 ( 36 – 18 ) / ( 30 – 18 )
 

Step 2: = 210

 

Example 2:
A city center has an average of 610 visitors on Sunday and 340 on other days. The average number of visitors per day  in a month of 30 days Beginning with a Sunday is.
 

Answer :
 

Since the month begins with a Sunday, So there will be five Sundays in the month
= ( 610 x 5 + 340 x 25 )/ 30
= 3050 + 8500 / 30
=11550 / 30 = 385.

 

Average Methods Example 4

Example 1:
The average of Six numbers is 25 and if one number of that average is cropped than the average occur is 26. Find the cropped number?
 

Answer :
 

here We can find the cropped number that is
 

Step 1: average of six number with cropped number is = (25 X 6) = 150 and average five number without cropped number is = (26 X 5) = 130.
 

Step 2: now the cropped number is = ( 150 – 130 ) = 20.
Here the cropped number is 20.
 

Example 2:  The average of 40 numbers is 20. If two numbers 36 and 30 are discarded then Find the average of  the remaining numbers ?
 

Answer :
 

Step 1 : At First we find the total number so ( 40 x 20 ) = 800. So sum 40 number is 800.two number discarded, so remaining 48 numbers is = ( 800 -( 36 + 30 ) = 734.
 

Step 2: Here we find required average is = 734 / 38 = 19.31. 

 

Average Methods Example 5

Example 1:
The average run of a cricket player of 8 innings was 34. How many runs must he make in his next innings so as to increase his average of runs by 6 ?
 

Answer :
 

Step 1: Average run of a player in next innings is 9 = ( 34 + 6 ) = 40 runs.
 

Step 2: Required run for 9 innings is ( 40 x 9 ) = 360 runs and 8 innings is ( 34 x 8 ) = 272 runs.
So, Required number of run is = (360 – 272 ) = 88 runs.

Example 2:
The average of five consecutive odd numbers A, B, C, D, and E is 45.what is the product of A and D ?
 

Answer :
A      B     C     D     E
43   44    45    46    47
So the Product of A and D is = ( 43 x 46 ) = 1978.

 

Average Methods Example 6

Example 1:
The average monthly income of A and B is Rs.6040. The monthly average income of B and C is Rs.7500 and monthly average income of A and C is Rs. 6500. Find the income of A in a monthly income ?
 

Answer: 
 

Step 1: here is ABC given respectively monthly income, hence we need to find both income.
( A + B ) = ( 6040 x 2 ) = 12080, ( B + C ) =( 7500 x 2 ) = 15000, ( C + A ) = ( 6500 x 2 ) = 13000
 

Step 2: If we add 3 income 2( A + B + C ) = 2 x ( 12080 + 15000 + 13000 ) = 40080 or A + B + C = 40080 / 2 = 20040.
Step 3: So we get the income of A Subtract income of ( A + B + C ) – ( B + C ) = (20040 – 15000 ) =5040.
 

Example 2:
The average of Five numbers is 62.The average of the second and the third number is 45.The average of the first and the fifth number is 66. What is the fourth number ?
 

Answer :
Average of Five numbers is = 62 x 5 = 310
Average of second and third number = 45 x 2 = 90
Average of first and fourth number = 66 x 2 = 132
( 132 + 90 ) = 222
The fourth number is ( 310 – 222 ) = 88