Problems Based On Ages Tips & Tricks

Problems Based On Ages Tips & Tricks

Example 1: The ratio of present age of A & B is 2 : 3 the present age of A is 30 years. Find the age of B after 5 years ?
Answer :

Step 1:  A : B present age ratio is 2 : 3 and A = 30 years.
 

Step 2: B present age is 30 / 2 x 3 = 45 years.
 

Step 3 : B age after 5 years is 45 + 5 = 50 years.

 

Example 2 : Niloy is as younger to Ganesh as he is older to Dev. If the sum of the ages of Ganesh & Dev is 58 years. What is Niloy age ?
Answer :

Step 1 : G – N = N – D
 

Step 2 : G + D = 2N
 

Step 3 :  58 = 2N
 

Step 4 : N = 29 years

 

Problems Based on years ago Ages Shortcut Tricks

 

Example 1 :
Suman and Bivash is 50 years old and  70 years old . How many years before was the ratio of their ages 3 : 5 ?
 

Answer :
Their ratio was  3 : 5 , Y years before ,
So, 50 – y / 70 – y = 3 / 5
5 ( 50 – y ) = 3 ( 70 – y )
250 – 5y = 210 – 3y
2y = 40
y = 20 years.

Example 2 :
The present ratio of ages of P & Q is 4 : 6 . If the sum of present ages of P & Q is 50 years. Find the ages of P & Q before 4 years.
 

Answer:
Let ages of P & Q is x , so P & Q ages are 4x and 6x Gradually.
Now according to question Sum of present ages ,
4x + 6x = 50, 10x = 50, x = 5 years, (We got the value of x = 5)
And than the present age of P is = 4x = 4 x 5 = 20 years.
So, years ago the age of P = ( 20 – 4 ) = 16 years, and present  age of Q is = 6x = 6 x 5 = 30 years.
So, years ago the age of Q = (30 – 4 ) = 26 years.

 

Example 3 :
Reeya is 28 years old and Rajib is 12 years . In how many years will Reeya be twice  as old as Rajib ?
 

Answer :
Let Reeya be in x years . Then
( 28 + x ) = 2 ( 12 + x )
28 + x = 24 + 2x
x = 4 years .

Example 4 :
The ratio of ages of P & Q after 5 years will be 3 : 5 . If the sum of ages of P & Q at present is 38 years . Find the ages of P & Q before 5 years .
 

Answer :
Let the ages of P & Q are 3x and 5x respectively after 5 years .
( 3x – 5 ) + ( 5x – 5 ) = 38 years
6x – 10 = 38 years
8x = 48 years
x = 6
The ages of P after 5 years
= 6 x 3
= 18 years
Then the ages of Q after 5 years
6 x 5 = 30 years
The ages of P & Q before 5 years is
P = ( 18 – 10 ) = 8 years
Q = ( 30 – 10 ) = 20 years .

 

Problems Based on Present Age Shortcut Tricks

Example 1 :
Ratio of ages of M & N 4 years ago was 3 : 5. If the sum of present ages of M & N is 64 years than , Find the present ages of M & N.
 

Answer:
Let the ages is M & N 4 years ago are 3x and 5x.
Hence,
( 3x + 4 )+( 5x + 4 ) = 64 years,
= 8x + 8 = 64, = 8x = 56, x = 7.  ( we get the value of x).
So the age of M , 4 years ago  = 7 x 3 = 21years,
and the age of N, 4 years ago = 7 x 5 = 35 years.
Now the present age of M is = ( 21 + 4 ) = 25 years,
and present age of N is = ( 35 + 4) = 39 years.

Example 2 :
Ratio of ages of M & N 4 years ago was 3 : 5. If the sum of present ages of M & N is 64 years than , Find the present ages of M & N.
 

Answer :
Step1:  M : N = 3 : 5 , According to Question ( P + Q ) = 64 years.
Sum of both ages 4 years ago is ( 64 – 8 ) = 56 , (say that before age that’s why subtract)
Step2:  M = ( 56 / 8 ) x 3 = 7 x 3 = 21 years
and N = (56 / 8 ) x 5 = 5 x 7 = 35 years,
Step3:  present age of M = ( 21 + 4 ) = 25 years
and present age of N = ( 35 + 4 ) = 39 years.

Example 3 :
At present , the ratio between the ages of Anil and  Anu is 4 : 3 . After 4 years , Anil’s age will be 24 years . What is the age of Anu at present ?
 

Answer :
Let the present age of Anil and Anu is 4x years and 3x years respectively.
So , After 4 years Anil’s age ,will be 24 ,
4x + 4 = 24
4x = 20
x = 5
So , Anu present age is 3x = 3 x 5 = 15 years .

 

Problems Based on after years Ages Shortcut Tricks

Example 1 :
The sum of present ages of a father and his son is 60 years, 6 years ago, father’s age was five times the age of the son. What will be After six years son’s age will be ?
 

Answer :
Step 1: let present age of son and father is x and (60 – x ) years, Then,
( 60 – x ) – 6 = 5 (x – 6 )
54 – x = 5x – 30
6x = 84
x = 14 years.
 

Step 2: Son’s age after six years is ( x + 6 ) = 14 + 6 = 20 years,

Example 2 :
Ratio of present ages of C & D is 4 : 6 . The present age of C is 40 years. Find the age of D after 6 years.
First we do Traditional way than we do shortcut way.
 

Answer :
Let the ages of C & D are 4x and 6x.
Hence,C = 4x = 40, = x = 10, ( So we get the value of x )
So the present age of D is = 6x = 6 X10 = 60 years, hence the age of D is  after 6 years 60 + 6 = 66 years.